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	<title>Comments for Guj800</title>
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	<link>http://guj800.wordpress.com</link>
	<description>Musings in technology, philosophy, and all things guj</description>
	<lastBuildDate>Wed, 04 Nov 2009 18:12:49 +0000</lastBuildDate>
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		<title>Comment on Calculated Items in Pivot Tables by Elena</title>
		<link>http://guj800.wordpress.com/2008/06/03/pivot-table-frustration/#comment-88</link>
		<dc:creator>Elena</dc:creator>
		<pubDate>Wed, 04 Nov 2009 18:12:49 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=4#comment-88</guid>
		<description>I have the same problem as Tania with Calculated Items and wonder if anyone has found an answer or can confirm that Microsoft intended for this to happen.</description>
		<content:encoded><![CDATA[<p>I have the same problem as Tania with Calculated Items and wonder if anyone has found an answer or can confirm that Microsoft intended for this to happen.</p>
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		<title>Comment on Calculated Items in Pivot Tables by Tania</title>
		<link>http://guj800.wordpress.com/2008/06/03/pivot-table-frustration/#comment-87</link>
		<dc:creator>Tania</dc:creator>
		<pubDate>Thu, 23 Apr 2009 16:21:46 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=4#comment-87</guid>
		<description>Here&#039;s a twist...

I have a pivot table with two row fields (Brand and Boutique).  When I add a calculated item to the data field, EVERY Boutique shows up for EVERY Brand even when none of the source data has these combinations.  Thus, each boutique is listed multiply times - within the Brand that it truly belongs, as well as in each of the other Brands.  Of course the values for all data in these unwanted data fields is blank with the exception of the calculated items which are #DIV/0.

When I take the Brand row field out of the pivot table, the boutiques each show up once.  But I really need the Brand rows, too.

Any ideas???</description>
		<content:encoded><![CDATA[<p>Here&#8217;s a twist&#8230;</p>
<p>I have a pivot table with two row fields (Brand and Boutique).  When I add a calculated item to the data field, EVERY Boutique shows up for EVERY Brand even when none of the source data has these combinations.  Thus, each boutique is listed multiply times &#8211; within the Brand that it truly belongs, as well as in each of the other Brands.  Of course the values for all data in these unwanted data fields is blank with the exception of the calculated items which are #DIV/0.</p>
<p>When I take the Brand row field out of the pivot table, the boutiques each show up once.  But I really need the Brand rows, too.</p>
<p>Any ideas???</p>
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	</item>
	<item>
		<title>Comment on Calculated Items in Pivot Tables by Leomar</title>
		<link>http://guj800.wordpress.com/2008/06/03/pivot-table-frustration/#comment-84</link>
		<dc:creator>Leomar</dc:creator>
		<pubDate>Wed, 18 Feb 2009 19:28:49 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=4#comment-84</guid>
		<description>Hi Micheline,

Try adding this as a calculated field (quantity*(price/price))

this will only work if you will not change prices. :)</description>
		<content:encoded><![CDATA[<p>Hi Micheline,</p>
<p>Try adding this as a calculated field (quantity*(price/price))</p>
<p>this will only work if you will not change prices. :)</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Create Your Own Excel Add-Ins by Tom Adler</title>
		<link>http://guj800.wordpress.com/2008/06/20/create-your-own-excel-add-ins/#comment-78</link>
		<dc:creator>Tom Adler</dc:creator>
		<pubDate>Wed, 27 Aug 2008 17:58:42 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=22#comment-78</guid>
		<description>I have had some trouble with this, everything works smoothly with the CAGR forumla, I went through all the steps and got to the very last part where you click it to be an add-in. After doing so I go back to my workbook and it locks the pane. The add-in will work but the rest of the excel file is froze. Or if I get the file to unfreeze then the formula won&#039;t work. I have searched to see if there is a security setting not allowing my add-in to work but it seems that all requirements are accounted for. 

Please help.</description>
		<content:encoded><![CDATA[<p>I have had some trouble with this, everything works smoothly with the CAGR forumla, I went through all the steps and got to the very last part where you click it to be an add-in. After doing so I go back to my workbook and it locks the pane. The add-in will work but the rest of the excel file is froze. Or if I get the file to unfreeze then the formula won&#8217;t work. I have searched to see if there is a security setting not allowing my add-in to work but it seems that all requirements are accounted for. </p>
<p>Please help.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Progressive Status Indicators in Excel by Progressive Status Indicators in Excel - Learn Excel</title>
		<link>http://guj800.wordpress.com/2008/07/10/progressive-status-indicators-in-excel/#comment-67</link>
		<dc:creator>Progressive Status Indicators in Excel - Learn Excel</dc:creator>
		<pubDate>Sun, 13 Jul 2008 07:57:10 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=42#comment-67</guid>
		<description>[...] Original post by J. D. Palmer [...]</description>
		<content:encoded><![CDATA[<p>[...] Original post by J. D. Palmer [...]</p>
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	<item>
		<title>Comment on Progressive Status Indicators in Excel by M. Palmer</title>
		<link>http://guj800.wordpress.com/2008/07/10/progressive-status-indicators-in-excel/#comment-66</link>
		<dc:creator>M. Palmer</dc:creator>
		<pubDate>Fri, 11 Jul 2008 22:00:12 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=42#comment-66</guid>
		<description>NP.  I just thought I&#039;d point that out before some other anonymous blago-whore did.</description>
		<content:encoded><![CDATA[<p>NP.  I just thought I&#8217;d point that out before some other anonymous blago-whore did.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Progressive Status Indicators in Excel by J. D. Palmer</title>
		<link>http://guj800.wordpress.com/2008/07/10/progressive-status-indicators-in-excel/#comment-65</link>
		<dc:creator>J. D. Palmer</dc:creator>
		<pubDate>Thu, 10 Jul 2008 17:27:07 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=42#comment-65</guid>
		<description>::sigh:: 

I thought I fixed that.  Thanks, good onion.</description>
		<content:encoded><![CDATA[<p>::sigh:: </p>
<p>I thought I fixed that.  Thanks, good onion.</p>
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	<item>
		<title>Comment on Progressive Status Indicators in Excel by M. Palmer</title>
		<link>http://guj800.wordpress.com/2008/07/10/progressive-status-indicators-in-excel/#comment-64</link>
		<dc:creator>M. Palmer</dc:creator>
		<pubDate>Thu, 10 Jul 2008 17:17:49 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=42#comment-64</guid>
		<description>&quot;...Dim intR As Integer
     Dim intY As Integer
     Dim intB As Integer...&quot;

Should &#039;intY&#039; be &#039;intG&#039;?</description>
		<content:encoded><![CDATA[<p>&#8220;&#8230;Dim intR As Integer<br />
     Dim intY As Integer<br />
     Dim intB As Integer&#8230;&#8221;</p>
<p>Should &#8216;intY&#8217; be &#8216;intG&#8217;?</p>
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	<item>
		<title>Comment on Getting Information From the Web Using Excel VBA by J. D. Palmer</title>
		<link>http://guj800.wordpress.com/2008/06/30/getting-information-from-the-web-using-excel-vba/#comment-63</link>
		<dc:creator>J. D. Palmer</dc:creator>
		<pubDate>Tue, 08 Jul 2008 12:33:10 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=36#comment-63</guid>
		<description>@JP, @Al, thank you for your input.  I have changed the code in the post per your suggestions.

@Al, you were right about the variable mismatch, but the function still will not work from my office computer.  It just exits the function after reaching the line &quot;Set inet1 = New Inet&quot;.  They lock these computers down pretty hard, so it may be a user restriction, or it could be a firewall issue.  As you know, the part that you found different on the Brittish msn site did not post, and I am interested to know the difference.  If you would be so kind as to repost, you can get the html string to post as text - rather than hypertext - by using { } instead of &lt; &gt;.  It will not be a literal representation, but we will get the point.</description>
		<content:encoded><![CDATA[<p>@JP, @Al, thank you for your input.  I have changed the code in the post per your suggestions.</p>
<p>@Al, you were right about the variable mismatch, but the function still will not work from my office computer.  It just exits the function after reaching the line &#8220;Set inet1 = New Inet&#8221;.  They lock these computers down pretty hard, so it may be a user restriction, or it could be a firewall issue.  As you know, the part that you found different on the Brittish msn site did not post, and I am interested to know the difference.  If you would be so kind as to repost, you can get the html string to post as text &#8211; rather than hypertext &#8211; by using { } instead of &lt; &gt;.  It will not be a literal representation, but we will get the point.</p>
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	<item>
		<title>Comment on Getting Information From the Web Using Excel VBA by Al</title>
		<link>http://guj800.wordpress.com/2008/06/30/getting-information-from-the-web-using-excel-vba/#comment-60</link>
		<dc:creator>Al</dc:creator>
		<pubDate>Tue, 08 Jul 2008 09:03:06 +0000</pubDate>
		<guid isPermaLink="false">http://guj800.wordpress.com/?p=36#comment-60</guid>
		<description>Hi J.D.

You&#039;ve mixed your variables a little - creating myhttp but using mypage in your inStr()

Also, they may have changed the site or it&#039;s different for Brits:&quot;&quot;
works for me:

Function Temp(strCity As String)
strCity = Replace(strCity, &quot;,&quot;, &quot;&amp;2C+&quot;)

Dim myURL As String
myURL = &quot;http://search.msn.com/results.aspx?q=current+temperature+&quot; &amp; strCity

Dim inet1 As Inet
Dim myhttp As String

Set inet1 = New Inet
With inet1
    .Protocol = icHTTP
    .URL = myURL
    myhttp = .OpenURL(.URL, icString)
End With
Set inet1 = Nothing

Dim intStart As Integer, intEnd As Integer
intStart = InStr(myhttp, &quot;&quot;) + 39
intEnd = InStr(intStart, myhttp, &quot;&amp;&quot;)

Temp = Mid(myhttp, intStart, (intEnd - intStart))
    
End Function</description>
		<content:encoded><![CDATA[<p>Hi J.D.</p>
<p>You&#8217;ve mixed your variables a little &#8211; creating myhttp but using mypage in your inStr()</p>
<p>Also, they may have changed the site or it&#8217;s different for Brits:&#8221;"<br />
works for me:</p>
<p>Function Temp(strCity As String)<br />
strCity = Replace(strCity, &#8220;,&#8221;, &#8220;&amp;2C+&#8221;)</p>
<p>Dim myURL As String<br />
myURL = &#8220;http://search.msn.com/results.aspx?q=current+temperature+&#8221; &amp; strCity</p>
<p>Dim inet1 As Inet<br />
Dim myhttp As String</p>
<p>Set inet1 = New Inet<br />
With inet1<br />
    .Protocol = icHTTP<br />
    .URL = myURL<br />
    myhttp = .OpenURL(.URL, icString)<br />
End With<br />
Set inet1 = Nothing</p>
<p>Dim intStart As Integer, intEnd As Integer<br />
intStart = InStr(myhttp, &#8220;&#8221;) + 39<br />
intEnd = InStr(intStart, myhttp, &#8220;&amp;&#8221;)</p>
<p>Temp = Mid(myhttp, intStart, (intEnd &#8211; intStart))</p>
<p>End Function</p>
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